Technical utilities

Voltage Divider Calculator

Divider output equals input voltage multiplied by the lower resistance divided by total series resistance. A connected load appears in parallel with the lower resistor.

Calculate two-resistor divider output, current, and the effect of an optional load resistor.

Enter values

Advanced assumptions

Calculated result

Divider output

Calculating…

Calculated locally in your browser

Planning math only. Verify equipment specifications and installation requirements separately.

Voltage divider relationship diagramAn original simplified resistor diagram paired with the current calculator result.V · I · R · PRESULTCalculated locallyFORMULA VISIBLEINPUTS EDITABLE
Voltage Divider Calculator relationship diagram. The illustration supports the text result; it is not a wiring or installation drawing.

What this calculator returns

A lower load resistance pulls the output below its unloaded value and increases source current.

Formula and variables

The calculation runs entirely in your browser. Static formulas, definitions, examples, and tables remain readable without JavaScript.

Formula

Vout = Vin × Rbottom/(R1 + Rbottom), where Rbottom = R2 || Rload when loaded.

V
Voltage across the modeled component or network.
I
Current through the modeled component or network.
R
Resistance in ohms; subscripts identify individual resistors.
P
Power dissipated or delivered, in watts.

R1 is the upper resistor; R2 and optional Rload form the lower equivalent resistance.

Worked example

Worked example inputs
InputValue
Input voltage12 V
Upper resistor R11000 Ω
Lower resistor R21000 Ω

12 V with R1 = 1 kΩ and R2 = 1 kΩ gives 6 V unloaded.

Reference table

Formula variants derived algebraically from Ohm's law, electrical power, divider, and resistor-network relationships.
Solve forFormula variants
VoltageV = I × R; V = P / I; V = √(P × R)
CurrentI = V / R; I = P / V; I = √(P / R)
ResistanceR = V / I; R = V² / P; R = P / I²
PowerP = V × I; P = I² × R; P = V² / R
NetworksSeries: Req = ΣR; parallel: 1/Req = Σ(1/R)

Frequently asked questions

Why does adding a load change divider voltage?

The load appears in parallel with the lower resistor, reducing the lower equivalent resistance and usually lowering output voltage.

Can a voltage divider power a large load?

This tool only models ideal steady-state resistors. A low-resistance load can change the output substantially and increase dissipation.

Assumptions and limitations

  • Ideal resistors and DC steady state.
  • No tolerance, noise, or transient model.

Method and sources

Review the electrical formulas, calculation methodology, and reference tables for the references most relevant to this calculation. The broader technical sources index records source scope and verification. Last reviewed .

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